| 世界锦标赛资格赛 2024 | 04/12 09:00 | 8 | 安迪•希克斯 v 龙泽煌 | 10-2 | |
| 世界锦标赛资格赛 2024 | 04/09 09:00 | 7 | 龙泽煌 v 悉尼•威尔森 | 10-1 | |
| 世界公开赛 2024 | 03/20 11:30 | 5 | 马克•塞尔比 v 龙泽煌 | 5-2 | |
| 世界公开赛 2024 | 03/18 06:30 | 6 | 斯佳辉 v 龙泽煌 | 2-5 | |
| 威尔士公开赛 2024 | 02/13 09:30 | 6 | 龙泽煌 v 安东尼•麦吉尔 | 1-4 | |
| 威尔士公开赛资格赛 2024 | 01/26 10:00 | 7 | 龙泽煌 v 安迪•李 | 4-1 | |
| 世界公开赛资格赛 2024 | 01/24 10:00 | 7 | 塔猜亚•乌诺 v 龙泽煌 | 4-5 | |
| 德国大师赛资格赛 2024 | 12/20 10:00 | 7 | 乔丹•布朗 v 龙泽煌 | 5-4 | |
| 苏格兰公开赛资格赛 2023 | 12/11 13:00 | 7 | 阿里•卡特 v 龙泽煌 | 4-3 | |
| 斯诺克单局限时挑战赛 2023 | 12/09 20:20 | 4 | 龙泽煌 v 斯蒂芬•霍尔沃斯 | 0-1 | |
| 斯诺克单局限时挑战赛 2023 | 12/09 14:55 | 5 | 杜安•琼斯 v 龙泽煌 | 0-1 | |
| 斯诺克单局限时挑战赛 2023 | 12/08 19:30 | 6 | 龙泽煌 v 诺蓬•桑坎 | 1-0 |
Long Zehuang (Chinese: 龙泽煌; born 28 December 1996) is a Chinese snooker player. He has achieved a place on the World Snooker Tour starting with 2023–24 snooker season.
Before becoming a professional snooker player, Long won World Junior 9-Ball Championships in 2015 when he was 18 years old.
Long played at the 2018 Haining Open, beating Liu Hongyu before losing to Cai Jianzhong.
He came close to qualifying for the Snooker World Tour in June 2019 but lost the final match in the final round of Q school to Barry Pinches.
He won a place on the 2023-24 World Snooker Tour by successfully qualifying from the CBSA qualifying events held in Beijing in April 2023. His place was earned with a victory over former professional Chen Feilong in the final qualifying round
Long made his debut in a professional draw at the 2023 Championship League held at the Morningside Arena in Leicester, England from 26 June 2023. He made an auspicious start, going unbeaten in the round-Robin group. He earned a credible draw against Jackson Page, before defeating world number 12 Ali Carter, and young Welshman Ryan Davies, to top the group and progress to the next stage. In the second round-robin he went undefeated, drawing with Sam Craigie, Jak Jones and Michael White. He secured a place at the latter stages of the World Open, winning 5-4 against Thepchaiya Un-Nooh.